Learn what resistors are, how resistance works, and how to calculate total resistance in series and parallel circuits.
Imagine walking through a narrow corridor compared to a wide hallway. The narrow corridor slows you down — it resists your movement. Electricity works in a very similar way. A resistor is a component in an electrical circuit that opposes (resists) the flow of electric current.
Resistors are one of the most common components found in electronic devices — phones, radios, televisions, computers, and countless other gadgets all use them.
Resistance is the measure of how much a component opposes the flow of electric current. The greater the resistance, the less current can flow.
The unit Ohm is named after the German physicist Georg Simon Ohm, who discovered the precise relationship between voltage, current, and resistance — a relationship we call Ohm's Law.
| Unit | Symbol | Equal to | Where used |
|---|---|---|---|
| Ohm | Ω | 1 Ω | Small resistors in everyday circuits |
| Kilohm | kΩ | 1 000 Ω | Audio and radio circuits |
| Megohm | MΩ | 1 000 000 Ω | High-voltage insulation testing |
When resistors are connected in series, they are joined end-to-end in a single line — like beads on a necklace. The electric current has only one path to follow, so it must pass through every resistor one after the other.
You simply add all the resistances together. For the circuit above:
• Current is the same through every resistor
• Voltage is shared (divided) across resistors
• Total R is always greater than any single resistor
Old-style Christmas lights are wired in series. If one bulb blows, the whole string goes out — because the single path is broken!
When resistors are connected in parallel, they are joined across the same two points, providing multiple paths for the current to flow through. The current splits between the branches.
Add the reciprocals ("1 divided by" each resistance), then flip the result. For the circuit above (3 Ω, 6 Ω, 6 Ω):
• Voltage is the same across all branches
• Current splits between branches
• Total R is always less than any single resistor
Home electrical wiring is parallel. Each room works independently. If one bulb breaks, the others stay on!
| Feature | Series | Parallel |
|---|---|---|
| Current paths | One path only | Multiple paths |
| Current (I) | Same everywhere | Splits at junctions |
| Voltage (V) | Shared / divided | Same across all branches |
| Total resistance | Always increases | Always decreases |
| Formula | R = R₁ + R₂ + … | 1/R = 1/R₁ + 1/R₂ + … |
For each question: first find the total resistance, then use Ohm's Law to calculate the answer. Click Show solution to check your work — but try it yourself first!
Two resistors, R₁ = 8 Ω and R₂ = 4 Ω, are connected in series to a 12 V battery. Calculate the current flowing in the circuit.
Step 1 — Find total resistance (series: add them)
Rtotal = R₁ + R₂ = 8 + 4 = 12 Ω
Step 2 — Apply Ohm's Law
I = V ÷ R = 12 V ÷ 12 Ω
∴ I = 1 A
Two resistors, R₁ = 6 Ω and R₂ = 12 Ω, are connected in parallel across a 6 V battery. Calculate the total current drawn from the battery.
Step 1 — Find total resistance (parallel: use reciprocals)
1/Rtotal = 1/6 + 1/12 = 2/12 + 1/12 = 3/12
Rtotal = 12 ÷ 3 = 4 Ω
Step 2 — Apply Ohm's Law
I = V ÷ R = 6 V ÷ 4 Ω
∴ I = 1.5 A
Three resistors of 5 Ω, 10 Ω, and 15 Ω are connected in series. A current of 2 A flows through the circuit. What is the voltage of the battery?
Step 1 — Find total resistance
Rtotal = 5 + 10 + 15 = 30 Ω
Step 2 — Apply Ohm's Law (finding V)
V = I × R = 2 A × 30 Ω
∴ V = 60 V
Three resistors of 4 Ω, 6 Ω, and 12 Ω are connected in parallel to a 12 V battery. What is the total resistance? How much current does the battery supply?
Step 1 — Find total resistance
1/Rtotal = 1/4 + 1/6 + 1/12 = 3/12 + 2/12 + 1/12 = 6/12
Rtotal = 12 ÷ 6 = 2 Ω
Step 2 — Apply Ohm's Law
I = V ÷ R = 12 V ÷ 2 Ω
∴ Rtotal = 2 Ω and I = 6 A
A 9 V battery is connected to three resistors in series: R₁ = 1 Ω, R₂ = 2 Ω, and R₃ = ?. The current in the circuit is 1.5 A. Find the value of R₃.
Step 1 — Find total resistance using Ohm's Law
Rtotal = V ÷ I = 9 V ÷ 1.5 A = 6 Ω
Step 2 — Solve for R₃
Rtotal = R₁ + R₂ + R₃
6 = 1 + 2 + R₃ → R₃ = 6 − 3
∴ R₃ = 3 Ω
Two identical resistors are connected in parallel. Their combined resistance is 5 Ω. What is the resistance of each individual resistor?
Key insight: When two equal resistors (each = R) are in parallel:
1/Rtotal = 1/R + 1/R = 2/R → Rtotal = R ÷ 2
Solve:
5 = R ÷ 2 → R = 5 × 2
∴ Each resistor = 10 Ω